HDU1004——Let the Balloon Rise-白红宇

HDU1004——Let the Balloon Rise

阅读量：5977 次

发布时间：2019-06-20

本文共 1404 字，大约阅读时间需要 4 分钟。

Problem Description

Contest time again! How excited it is to see balloons floating around. But to tell you a secret, the judges' favorite time is guessing the most popular problem. When the contest is over, they will count the balloons of each color and find the result.

This year, they decide to leave this lovely job to you.

Input

Input contains multiple test cases. Each test case starts with a number N (0 < N <= 1000) -- the total number of balloons distributed. The next N lines contain one color each. The color of a balloon is a string of up to 15 lower-case letters.

A test case with N = 0 terminates the input and this test case is not to be processed.

Output

For each case, print the color of balloon for the most popular problem on a single line. It is guaranteed that there is a unique solution for each test case.

Sample Input

       5 green red blue red red 3 pink orange pink 0 

Sample Output

       red pink 

分析：map第二弹~

#include
     
      #include
      
       #include
       
        #include
        
         #include
         
          #include
          
           #include
           
            #include
            
             #include
             
              #include
              
               #include
               using namespace std;int main(){ int n; string color,s; map
                
                 Balloon; while(scanf("%d",&n)&&(n!=0)) { Balloon.clear(); for(int i=0;i
                 
                  >color; Balloon[color]++; } int max=-1; map
                  
                   ::iterator p; for(p=Balloon.begin();p!=Balloon.end();p++) { if((*p).second>max) { max=(*p).second; s=(*p).first; } } cout<
                   <

转载地址：http://hpsox.baihongyu.com/

你可能感兴趣的文章